2a-[b+(b+5a)-(3a-4b)]=

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Solution for 2a-[b+(b+5a)-(3a-4b)]= equation:


Simplifying
2a + -1[b + (b + 5a) + -1(3a + -4b)] = 0

Reorder the terms:
2a + -1[b + (5a + b) + -1(3a + -4b)] = 0

Remove parenthesis around (5a + b)
2a + -1[b + 5a + b + -1(3a + -4b)] = 0
2a + -1[b + 5a + b + (3a * -1 + -4b * -1)] = 0
2a + -1[b + 5a + b + (-3a + 4b)] = 0

Reorder the terms:
2a + -1[5a + -3a + b + b + 4b] = 0

Combine like terms: 5a + -3a = 2a
2a + -1[2a + b + b + 4b] = 0

Combine like terms: b + b = 2b
2a + -1[2a + 2b + 4b] = 0

Combine like terms: 2b + 4b = 6b
2a + -1[2a + 6b] = 0
2a + [2a * -1 + 6b * -1] = 0
2a + [-2a + -6b] = 0

Combine like terms: 2a + -2a = 0
0 + -6b = 0
-6b = 0

Solving
-6b = 0

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Divide each side by '-6'.
b = 0

Simplifying
b = 0

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